[tex]( \sqrt[3]{2} )^x \ \textgreater \ \frac{1}{8}
[/tex]
[tex] 2^{ \frac{1}{3}x } \ \textgreater \ 2^{-3}
[/tex]
[tex]
folosind a^x\ \textgreater \ a^y [/tex]
[tex] \frac{1}{3}x \ \textgreater \ -3
[/tex]
[tex]x \ \textgreater \ -9[/tex]
deci folosesti a^x > a^y si a > 1 si x>y
