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exercitiul 2
va rog ajutatima.


Exercitiul 2va Rog Ajutatima class=

Răspuns :

[tex]a) \frac{75}{5 \sqrt{3}}= \frac{75 \sqrt{3}}{5\cdot3}}=15 \sqrt{3} \\ \frac{42}{7 \sqrt{2}} = \frac{42 \sqrt{2} }{7\cdot2} =3 \sqrt{2} \\ \\ \frac{18}{3 \sqrt{2}} = \frac{18 \sqrt{2} }{3\cdot2} =3 \sqrt{2} \\ \\ \frac{45}{5 \sqrt{3}} = \frac{45 \sqrt{3} }{5\cdot3} =3 \sqrt{3} [/tex]

[tex] \frac{75}{5 \sqrt{3}}= \frac{75 \sqrt{3}}{5\cdot3}}=15 \sqrt{3} \\ \frac{42}{7 \sqrt{2}} = \frac{42 \sqrt{2} }{7\cdot2} =3 \sqrt{2} \\ \\ \frac{18}{3 \sqrt{2}} = \frac{18 \sqrt{2} }{3\cdot2} =3 \sqrt{2} \\ \\ \frac{45}{5 \sqrt{3}} = \frac{45 \sqrt{3} }{5\cdot3} =3 \sqrt{3} [/tex]

[tex]\frac{24}{2 \sqrt{6}} = \frac{24 \sqrt{6} }{2\cdot6} =2 \sqrt{6} \\ \\ \frac{6}{3 \sqrt{2}} = \frac{6 \sqrt{2} }{2\cdot3} = \sqrt{2} \\ \\ \frac{15}{ \sqrt{3}} = \frac{15 \sqrt{3} }{3} =5 \sqrt{3} [/tex]