mr=masa de C reacționată
mi=masa de C introdusă
mi=250Kg
P=puritate
P=85%
P=mr/mi×100
mr=p×mi/100
mr=85×250/100=212,5 Kg
1.
212,5Kg.........x
2 C + O2 = 2 CO
2×12............2×28
Mc=Ac=12g/mol
Mco=Ac+Ao=12+16=28g/mol
X=(212,5×2×28)/(2×12)=495,83 Kg CO
2.
212,5Kg........y
.....C + O2=CO2
......12..............44
Mc=Ac=12g/mol
MCO2=Ac+2Ao=12+2×16=44g/mol
Y=212,5Kg×44/12=779,16 Kg CO2