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Calculati:

a) 15 intrgi si 3 supra 5 - 12- 2 intregi si 1 supra 3=

Vreau rezolvare nu direct raspuns!!


Răspuns :

15 intregi si 3/5 =(15x5+3) /5=(75+3) /5= 78/5
2 intregi si 1/3=(2x3+1) /3=7/3
78/5-12-7/3  le aducem la acelasi numitor 5x3=15
(78x3) /15 -(12x15)/15 -(7x5) /15=
=234 /15- 180/15-35/15=
=54/15-35/15=
=19/15=
=1 intreg si 4/15