1)897-168=729 ramase dupa prima zi
729-729/3=486 ramase dupa a doua zi => 486 flori ramase
2) c=2g
13c+8g=136
8g=4c=>17c=136=>c=136/17=8 lei costa un creion
Deci o guma =8/2=4
3)a)m:n=p
m+n+p=107
m+n=81
m+p=104
n=107-104=3
m+3=81=>m=78
p+81=107=>p=26
78:3=26
b)a:b=c,rest r
a+b+c+r=91
b+c+r=28=>a=91-28=63
a+r=74=>r=74-63=11
b si r sunt numere consecutive impare=>b=13 si c=4
63:13=4, rest 11