notezi p=x^2-4x+3 . daca f se divide la p atunci f are radacinile ecuatiei px=0
rezolvi ecuatia
x^2-4x+3=0
x1=1
x2=3=> f(1)=0
f(1)=1-4+1+a+b=0 a+b=2
f(3)=0
f(3)=3^4-4*3^3+3^2+3a+b=0
81-108+9+3a+b=0
-18=3a+b
rezolvi sistemul
{a+b=2
{3a+b=-18
din ec2 scai ec1
3a+b-a-b=-18+2
2a=-16 a=-16:2=-8
Inlocuiesti in prima ecuatie
-8+b=2=>b=10
