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In triunghiul DEF cu D= 90 gr , construim mediana DM si inaltimea DN. Daca DM=15 cm si DN =10 cm , aflati aria DEF


Răspuns :

ΔDEF- dreptunghic |
DM- mediana          | ⇒ [tex]DM= \frac{EF}{2} [/tex] => DM=EM=MF=15 cm=> 
DM= 15 cm             |


=> EF= 30 cm

[tex] A_{tr.dr} = \frac{h*ip}{2}= \frac{10*30}{2}= \frac{300}{2}= 150cm^{2} [/tex]