a) (1/3: 2 intregi 2/3+1)⁴:(-9/8)³ =
(1/3:8/3+1)^4:(-9/8)^3 =
(1/3*3/8+1)^4:(-9/8)^3 =
(9/8)^4:(-9/8)^3 = -9/8
b) [(-1/4)^8:(-1/4)^6]⁴:(-3/12)^6 =
((-1/4)^2)^6 : (3/12)^6 =
(-1/4)^8:3^6/12^6 =
(1/4)^8*12^6/3^6 =
2^-16*4^6 = 2^-16*(2^2)^6 = 2^-16*2^12 = 2^-4 = 1/2^4 = 1/16
„CLAUAND„
