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URGENT! 50 puncte!!
Rezolvati in Q ecuatia:
1+[tex] \frac{1}{1+2} [/tex]+[tex] \frac{1}{1+2+3} [/tex]+...+[tex] \frac{1}{1+2+3+...+n} [/tex]=[tex] \frac{4024}{2013} [/tex]
n∈N*



Răspuns :

Frumos si elegant. Vezi poza, te rog!
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Vezi imaginea CHRIS02JUNIOR