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(11+22+.....+110)÷5+3^2

Răspuns :

In paranteza dai factor comun pe 11 si ai: [11(1+2+3+..+10)]:5+9=
=(11* 10*11 supra 2):5+9= 605:5+9=121 + 9 = 130
(11+22+.....+110)÷5+3^2 = 
11
×( 1+2+....+10) ÷5 + 9 =
11× (10 ×11 ÷2) ÷5 + 9 = 
11× 55 ÷ 5 + 9 =
11 × 11 + 9 = 
121 + 9 =
130