[tex]1,1(3)= \frac{113-11}{90}= \frac{102}{90}= \frac{51}{45} \\ \\ 2,07(27)= \frac{20727-207}{99900}= \frac{20520}{999000} } = \frac{1026}{59950}= \frac{513}{24975} \\ \\ \frac{51}{45}-\frac{513}{24975} = \frac{51\cdot555-513}{24975} = \frac{27792}{24975} \\ \\ 1,1(3)- 2,07(27)=\frac{27792}{24975} [/tex]
