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(2100+2550):(450+5100)=
100,50,50,100 sunt puteri
adica 2 la puterea 100...asa mai departe


Răspuns :

(2^100 + 25^50) : (4^50 + 5^100) =

= (2^100 + 5^100) : (2^100 + 5^100) =

= 1
(2¹⁰⁰+25⁵⁰)÷(4⁵⁰+5¹⁰⁰)=
=(2¹⁰⁰+5²ˣ⁵⁰)÷(2²ˣ⁵⁰+5¹⁰⁰)
=(2¹⁰⁰+5¹⁰⁰)÷(2¹⁰⁰+5¹⁰⁰)=1