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Afla factorul comun . Aplicati : daca a=16 si b+c=25 afla : ab+ac=? 2a+3b+3c=?

Răspuns :

Ab+ac=?
a(b+c)=16•25=400

2a+3b+3C=?
2•16+3(b+c)=32+3•25=32+75=107

ab+ac= a×( b+c)= 16× 25= 400
2a+3b+3c= 2×16 + 3×( b+c)= 32+ 3×25= 32+ 75= 107

Sper ca te.am ajutat!!!!