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Determina numarul a din ecuatia [(5×a+19)×7-2]÷9=34

Răspuns :

(5×a+19)×7-2=306
(5×a+19)×7=308
5×a+19=308:7
5×a+19=44
5×a=25
a=25:5
a=5
[(5*a+19)*7-2]:9=34
[(5*a+19)*7-2]:9=34
[35*a+133-2]=34*9
35*a=306-131
a=175/35
a=5