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Suma a 5numere naturale consecutive este 5% din 1900.Sa se afle numerele.

Răspuns :

(1900-5):5=3799-1nr.
3799+1=3800-2nr.
3800+1=3801-3nr.
3801+1=3802-4nr.
3802+1=3803-5nr

Notez cu x, x+1, x+2, x+3, x+4 cele 5 numere

[tex]x+x+1+x+2+x+3+x+4=\frac{5}{100}*1900[/tex]

[tex] 5x+10=5*19[/tex]

[tex] 5x+10=95[/tex]

[tex] 5x=95-10[/tex]

[tex]5x=85[/tex]

[tex]x=85:5[/tex]

[tex]x=17[/tex]

x+1=17+1=18
x+2=17+2=19
x+3=17+3=20
x+4=17+4=21

Raspuns: cele 5 numere consecutive sunt: 17, 18, 19, 20 si 21.