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1 [tex] \frac{3}{8} [/tex] +(-1)+[tex] \frac{2}{3} [/tex]+([tex] \frac{-1}{6} [/tex])=

Răspuns :

1[tex] \frac{3}{8} -1+ \frac{2}{3}- \frac{1}{6}= [/tex]
=[tex] \frac{11}{8} -1+ \frac{2}{3}- \frac{1}{6} = \frac{11-24+16-4}{24}= -\frac{1}{24} [/tex]
Am adus la acelasi numitor.