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DAU COROAANAA ! Rezolvati in R ecuatia:
a) 5^2x + 5^x -600=0


Răspuns :

Notam  5^x = t

t^2 + t -600 =0
delta = 1+2400 = 2401 = 49^2
t1= (-1+49)/2 = 24
t2= (-1-49)/2 = - 25 < 0 (nu convine)

5^x = 24
log₅(5^x) =log₅(24)
x=log₅(24)