[tex]\it \dfrac{11}{3} =\dfrac{9+2}{3}=\dfrac{9}{3} +\dfrac{2}{3} =3+\dfrac{2}{3} =3\dfrac{2}{3}
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\dfrac{19}{4} =\dfrac{16+3}{4}=\dfrac{16}{4} +\dfrac{3}{4} =4+\dfrac{3}{4} =4\dfrac{3}{4}
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\dfrac{15}{5} = 3;\ \ \dfrac{60}{12}=5;\ \ \dfrac{44}{7} = \dfrac{42+2}{7} =6\dfrac{2}{7}[/tex]
[tex]\it \dfrac{19}{7} =\dfrac{14+5}{7}=2\dfrac{5}{7};\ \ \dfrac{66}{11} =6;\ \ \dfrac{100}{3} =\dfrac{99+1}{3} =33\dfrac{1}{3}
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\dfrac{37}{8} =\dfrac{32+5}{8}=4\dfrac{5}{8};\ \ \dfrac{32}{4} =8;\ \ \dfrac{29}{15}=\dfrac{15+14}{15} =1\dfrac{14}{15}[/tex]
