1)l=5,6hm=560 m
1hm=100m
L=27 dam=270 m
1 dam=10m
Aria dreptunghi=L•l=270•560=151.200 m²
2)(35+34+32):3=101:3=33,6°
150+100+250=500l apă de temperatură 33,6°
3)c/100=md/ms
5/100=md/450
md=22,5
1)35:x=y rest 5=>30:x=y
50:x=z rest 5=>45:x=z
65:x=w rest 5=>60:x=w
cmmdc al 30,45,60 este 15=>X=15
2)|x-2|=7
1.x-2=7=>x=7+2=9
2.x-2=-7=>x=-7+2=-5
