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In triunghiul ABC AC=4, BC=6 m(B^)=30 grade. Calculati sin A.

Răspuns :

Salut,

Teorema sinusurilor:

[tex]\dfrac{AC}{sinB}=\dfrac{BC}{sinA},\ deci\ sinA=\dfrac{BC\cdot sinB}{AC}=\dfrac{6\cdot \dfrac{1}2}{4}=\dfrac{3}4.[/tex]

Simplu, nu ?

Green eyes.