Notam cu a , b si c cele 3 numere naturale
a : b = 2 rest 3
a = 2×b + 3
b : c = 2 rest 3
b = 2×c + 3
a - c = 39
a /-----/-----/-----/-----/+3+6
b /-----/-----/+3
c /-----/
a - c = 3 segmente egale + 3+6 = 39
39 - (3+6) = 39 - 9 = 30
30 : 3 = 10 (un segment egal)
a = 4×10+9 = 49
b = 2×10+3 = 23
c = 10
verificare:
49 - 10 = 39
49 : 23 = 2 rest 3
23 : 10 = 2 rest 3
Raspuns:
a = 49
b = 23
c = 10