(2x + √3)(2 - x√3) = 1
Desfacem parantezele
4x - 2x²√3 + 2√3 - 3x = 1
Pastram radicalli intr o parte
x - 1 = 2√3x² - 2√3
x - 1 = 2√3 ( x² - 1)
x-1 = 2√3 (x-1)(x+1)
2√3(x-1)(x+1) - (x-1) = 0
(x-1)[ 2√3(x+1) + 1 ] = 0
=> x -1 = 0 => x₁ = 1
=> 2√3(x+1) +1 = 0
=> x+1 = -1 / 2√3
=>x+1 = -√3/ 6
=> x₂ = (-√3 - 6)/6
Niciodata nu impartii printr o expresie cu X, reduci numarul de solutii
