sunt sumele lui Gauss
1+2+3+...+n = n(n+1)/2 unde n este ultima cifra.
1+2+3+....+2006 = 2006*2007/2
1003*2007= 2 013 021
2+4+6+...+2006 =
2(1+2+3+...+1003)
Gauss in paranteza
1003*1004/2
deci 2* 1003*1004/2 simplificam 2 cu 2
1003*1004 = 1007012
1+3+5+...+2005
Aici se aplica alta formula
1+3+5+7+9+11+....+2n-1 = n*n
1+3+5+...+2005 =
2n-1=2005
2n=2006
n=1003
Deci 1+3+5+...+2005=1003*1003=1006009