1. C6H5-NH2 + (CH2-CH2)O = C6H5-NH-CH2-CH2OH
n anilina pura = 0,8x348,75/93 = 3 kmoli m produs = 0,75 x 3 x 137 = 308,25kg
2. CxH(2x-7)-NH2 + HONO + HCl = CxH(2x-7)-N≡N]⁺Cl⁻ + 2H2O
(A) (B)
CxH(2x-7)-N≡N]⁺Cl⁻+ H2O = CxH(2x-7)-OH (C)+ HCl + N2↑
nA = 21,4/M = nN2 = 4,48/22,4 = 0,2 moli
⇒ M = 21,4/0,2 =107 g/mol 14x + 9 = 107 14x = 98 x = 7
A = CH3-C6H4-NH2 B = CH3-C6H4-N≡N]⁺Cl⁻ C = CH3-C6H4-OH