5 tururi...........12 min
3 tururi...........10 min
12=2²×3
10=2×5
cmmmc=2²×3×5=60
deci
5×5 tururi...........12 min×5
3×6 tururi...........10 min×6
adica
25 tururi...........60 min
18 tururi...........60 min
deci dupa 18 tururi facute de miron se vor regasi in acelasi timp pe linia de sosire