a+b+c=145
a/b=3 rest 3⇒a=3b+3
c/a=3 rest 3⇒c=3a+3⇒c=3(3b+3)+3.
Si acum inlocuim in prima relatie in functie de b
(3b+3) + b +[3(3b+3)+3]=145
3b+3+b+[9b+9+3+3]=145
4b+3+9b+15=145
13b+18=145
13b=145-18
13b=127
b=127/13
a=3×127/13+3=381/13+3=420/13
c=3×420/13+3=1260/13+3=1299/13