AB/AC=3/4=k
Rezulta AB=3k si AC=4k
Aria triunghi dreptunghic =AB×AC/2=384
3k×4k=384×2=768
12k²=768⇒k²=64
Deci k=8
Acum putem afla AB=24 si AC=32
Cu t lui Pitagora aflam BC= √AB²+AC²=40
Perimetrul=24+32+40=96
A=AD×BC/2
384=AD×40/2. ⇒AD=19,2
Sin B=AC/BC=32/40
cosB=AB/BC=24/40
sinC=AB/BC=24/40
cosC=AC/BC=32/40
