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Calculati media geometrica a numerelor a=2 la 3+1 si b=3+3:3

Răspuns :

a=2³+1=8+1=9
b=3+3:3=3+1=4
Media geometrica = √a•b =√9•4=√36=6


[tex]\it m_g=\sqrt{a\cdot b} =\sqrt{(2^3+1)\cdot(3+3:3)} =\sqrt{9\cdot4} =3\cdot2=6[/tex]