0,5x+1=3⇔ 1 [tex]*[/tex]x+1=3⇔ 1 [tex]*[/tex]x=3-1⇒ 1 [tex]*[/tex]x=2
2 2 2
[tex]x= 2: \frac{1}{2} \to x=2*2 \to \boxed{x=4}[/tex]
[tex] \sqrt{3} x-5\ \textgreater \ 1 \to \sqrt{3} x \ \textgreater \ 1+5 \to \sqrt{3} x \ \textgreater \ 6\ \textless \ =\ \textgreater \ x\ \textgreater \ \frac{6}{ \sqrt{3} } \to \boxed{x\ \textgreater \ 2 \sqrt{3} } \\ \frac{6}{ \sqrt{3} } = \frac{ \not6 \sqrt{3} }{\not3} =2 \sqrt{3} \\ \\ Amplificam \text{ } cu \text{ } \sqrt{3} [/tex]
