[tex]\displaystyle\\
\text{Calculam ipotenuza i a triunghiului dreptunghic al bazei.}\\\\
i= \sqrt{0,7^2 + 2,4^2}= \sqrt{0,49 + 5,76}=\sqrt{6,25}=\boxed{2,5~cm}\\\\
a)\\
A_l = P_b \times h = (0,7+2,4+2,5)\times 10 =5,6\times 10= \boxed{56~cm^2}\\\\
A_b = \frac{0,7 \times 2,4}{2} = 0,7 \times 1,2 = \boxed{0,84 ~cm^2}\\\\
A_t = 2\times A_b + A_l = 2\times 0,84 + 56 = 1,68+56=\boxed{57,68~cm^2}\\\\
b)\\
V = A_b \times h = 0,84 \times 10 = \boxed{8,4~cm^3} [/tex]
