👤

rezolvati ecuatia

2[tex] sin^{2} [/tex] - 3cosx=0


Răspuns :

Ecuatia devine : 2(1-cos²x)-3cosx=0, de unde 2cos²x+3cosx-2=0, cu radacinile cosx=-2 nu corespunde, si cosx=1/2, deci:
 x∈{π/3+2kπ|k∈Z}∪{-π/3+2kπ|k∈Z}.