Notam:
a = prima zi
b = a 2-a zi
c = a 3-a zi
a+b+c = 1 300 km
a = b - 70 => b = a + 70
c = b + 20
a |____|
b |____|+70
c |____|+20 +70
avem 3 segmente egale +70 + 20 +70 = 1 300
1 300 - (70+20+70) = 1 300 - 160 = 1 140
1 140 : 3 = 380 (un segment egal)
a = 380
b = 380 + 70 = 450
c = 380 + 20 +70 = 470
Verificare:
380 + 450 + 470 = 1 300
380 km a parcurs in prima zi
450 km a parcurs in a 2-a zi
470 km a parcurs in a 3-a zi