abcd=13m+2
abcd=31n+2
13m=31n
77≤m≤769
33≤n≤322
m=31n/13 ⇒ n trebuie sa se divida cu 13 deci n=13k
n∈{3*13, 4*13, 5*13, ...........24*13}
m∈{3*31, 4*31, 5*31.............24*31}
abcd=13m+2
abcd={13*3*31+2, 13*4*31+2, .......................13*24*31+2}
abcd=31n+2
abcd=(31*3*13+2, 31*4*13+2, ........................31*24*13+2}
se obtin aceleasi rezultate
abcd={1211, 1614, ........................................9674}
incearca sa intelegi ce scrie mai sus si te lamuresc daca ceva e neclar
daca va fi cazul corectam greselile
