[tex]5\dfrac{1}{4}+7,04-\left(8\dfrac{1}{25}-13,75\right)-12,(3)=\\
\dfrac{21}{4}+\dfrac{704}{100}-\dfrac{201}{25}+\dfrac{1375}{100}-12\dfrac{3}{9}=\\
\\
\dfrac{21}{4}+\dfrac{176}{25}-\dfrac{201}{25}+\dfrac{55}{4}-12\dfrac{1}{3}=\\
\\
\dfrac{76}{4}-\dfrac{25}{25}-\dfrac{37}{3}=\\
19-1-\dfrac{37}{3}=\\
18-\dfrac{37}{3}=\dfrac{54-37}{3}=\boxed{\dfrac{17}{3}}[/tex]