[tex]x^2-6x+y^2-10y+34=0\\
(x^2-6x+9)+(y^2-10y+25)=0\\
(x-3)^2+(y-5)^2=0\\
\text{Dar cum:}(x-3)^2+(y-5)^2\geq 0,\text{ceea ce implica:}\\
\left \{ {{x-3=0} \atop {y-5=0}} \right.\Leftrightarrow \left \{ {{x=3} \atop {y=5}} \right. \\
S:(x,y)=(3,5)[/tex]
