a+b+c+d = 2 380
a = b:2 => b = 2×a
b = c:2 => c = 2×b
d = 3c/4
a |____|
b |____|____|
c |____|____|____|____|
d |____|____|____|
avem 10 segmente egale = 2 380
2 380 : 10 = 238 ( un segment egal )
a = 238
b = 2×238 = 476
c = 4×238 = 952
d = 3×238 = 714
Verificare:
238+476+952+714 = 2 380
a = 238
b = 476
c = 952
d = 714
