a+b+c = 502
a = b:2-37
c = 2×a-37
a |____|-37
b |____|____|
c |____|____|-37 -(2×37)
avem 5 segmente egale -(37+37+2×37) = 502
37+37+2×37 = 74+74 = 148
502 + 148 = 650
650 : 5 = 130 ( un segment egal)
a = 130-37 = 93
b = 2×130 = 260
c = 2×130-(37+2×37) = 260-111 = 149
Verificare:
93 + 260+149 = 502
a = 93
b = 260
c = 149