[tex] \frac{(3 \sqrt{3}-2 )+(3 \sqrt{3} +2) }{2} =\ \textgreater \ \frac{3 \sqrt{3}-2+3 \sqrt{3}+2}{2} =\ \textgreater \ \frac{ 6\sqrt{3} }{2} =\ \textgreater \ 3 \sqrt{3} [/tex]≈[tex]5,19615[/tex]
[tex](3 \sqrt{3} -2)(3 \sqrt{3} +2)=\ \textgreater \ 9*3-4=\ \textgreater \ 27-4=\ \textgreater \ 23[/tex]
am scris doua deoarece nu sunt sigur daca-i "+" sau"-" ....
[tex]Succes[/tex]
