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log5(4-√11) + log5(4+√11)

Răspuns :

log5 (16-11)=log5 (5)=1
Log5(4-√11) + log5(4+√11)

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[tex]\it log_5(4-\sqrt{11})+ log_5(4+\sqrt{11}) = log_5(4-\sqrt{11})(4+\sqrt{11})= \\\;\\ =log_5(4^2-(\sqrt{11})^2) = log_5(16-11)=log_55 = 1[/tex]