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rezolvati in multimea numerelor reale ecuatia!! helpp [tex]3- \sqrt{ x^{2} +3} =x[/tex]


Răspuns :

[tex]3-x= \sqrt{x^2+3} \\ x \leq 3 \\ (3-x)^2= x^{2} +3 \\ 9-6x+ x^{2} = x^{2} +3 \\ 6=6x \\ x=1[/tex]