La a Se scot factorii de sub radical si apoi se rationalizeaza numitorii:
[tex] \sqrt{8}=2 \sqrt{2} [/tex]
[tex] \sqrt{18}=3 \sqrt{2} [/tex]
[tex] \sqrt{32}=4 \sqrt{2} [/tex]
[tex]a= \frac{1}{ \sqrt2 } + \frac{2}{2\sqrt2}+ \frac{3}{3\sqrt2}+ \frac{4}{4\sqrt2} [/tex]
Se simplifica fractiile
Se obtine
[tex]a= \frac{1}{ \sqrt2 } + \frac{1}{\sqrt2}+ \frac{1}{1\sqrt2}+ \frac{1}{1\sqrt2} [/tex]
[tex]a= 4\frac{1}{ \sqrt2 } [/tex]
Rationalizam amplificand cu √2.
a=4√2/2
a=2√2
b) facem calculele de sub radicali.
La numarator: [tex] \sqrt{13^2-5^2}= \sqrt{169-25}= \sqrt{44} =2 \sqrt{11} [/tex]
La numitor: [tex] \sqrt{10^2-8^2}= \sqrt{100-64}= \sqrt{36} =6 [/tex]
Deci b=[tex] \frac{2 \sqrt{11}} {6}= \frac{ \sqrt{11} }{3} [/tex]
(dupa ce am simplificat fractia cu 2)
