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Suma a trei nr. consecutive impare este 4305 .Sa se afle nr. METODa grafica

Răspuns :

|________| a
|________|__2__| a+2
|________|__2__|__2__| a+4

3a+6=4305
3a=4305-6
3a=4299
a=4299:3
a=1433
a+2=1433+2=1435
a+4=1433+4=1437

Nr.sunt: 1433,1435,1437

a+b+c=4305
b=a+2
c=a+2+2=b+2

a |__|
b |__|+2|
c |__|+2|+2|
4305-6=4299
4299:3=1433 (a)
1433+2=1435 (b)
1435+2=1437 (c)