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calculati ( 2+i ) (3-2i ) (-(1-i )

Răspuns :

(2+i)(3-2i)*[-(1-i)]=(6+3i-4i-2i²)*(-1+i)=(6-i-(-1)*(-1+i)=
(6-i-1)*(-1+i)=(5-i)*(-1+i)=-5+i+5i-i²=-5+6i-(-1)=-4+6i