1 mol Mg contine 6,023*10²³ atomi , iar fiecare atom de Mg are 12 e⁻ , deci 1 mol Mg contine 12*6,023*10²³=72,276*10²³=7,2276*10²⁴ e⁻.Nr de moli de Mg care contin nr de e⁻ specificati in cerinta este :
[tex]\frac{2,4*6,023*10^{24}}{7,2276*10^{24}}=2[/tex]
2Mg+O2=2MgO
[tex]V_m=22,4l[/tex]
[tex]V_O=22,4l(raspuns \ corect=a)[/tex]
