11:
m=nr initial mere ; n,c,d sunt resturile din fiecare saptamana
m-3/6m=n;
n-6/12n=c
c-(1/3c+4)=d
d-(1/2d + 2)=8 (astea sunt datele problemei)
si incepem sa rezolvam ultima ecuatie:
d-(1/2d+2)=8 =>d-1/2d-2=8
d-1/2d=10
1/2d=10 (am adus la acelasi numitor la d)
d=20
c-1/3c-4=d=20
c-1/3c=24
(3c-c)/3=24 (am adus la acelasi numitor c)
2c/3=24
2c=72
c=72/2=36
n-6/12n=c=36
n-1/2n=36 (simplifici prin 6 fractia 6/12)
1/2n=36
n=72
m-3/6m=72
m-1/2m=72
1/2m=72
m=144 (nr initial de mere)
