1mol 1mol 1mol
NH3 + HNO3---> NH4NO3
x=5mol y=5mol 5mol
V= nxVm
V.NH3= 5molx22,4l/mol=.........................
m= nxM
m,HNO3= 5molx63g/mol= 315g-> este masa de acid care se afla dizolvata,md, in solutia40%
c=mdx100/ms
40/100= 315/ms--------------> calculeaza ms !!!!!