63.5 g/mol 98 g/mol 159.6 g/mol 2g/mol
Cu + H2SO4 =t⁰C=> CuSO4 + H2
1.6 g x g y g z g
63.5 ....98 .....159.6 ... 2
1.6 ......x .........y..........z
x= 1.6 * 98 / 63.5 = 2.46 g H2SO4 (md)
y=1.6 * 159.6 / 63.5= 4.02 g CuSO4 anhidru
z=1.6 * 2 / 63.5 = 0.05 g H2
a) ms H2SO4 = md * 100/c => ms H2SO4 = 2.46 * 100 / 70 = 3.51 g sol H2SO4 70%
b) m CuSO4= 4.02 g CuSO4 anhidru
c) m H2O = ms-md => 3.51 - 2.46 = 1.05 g H2O
d) V gaz = n * 22.4 l/mol
n= 0.05 g/ 2 = 0.025 mol H2
V H2 = 0.025 * 22.4 = 0.56 L H2 (cn)
