aflam cat din lucrare executa cei 10 m in 18 zile
10 m ...................24 z..................1 lucrare
10m .....................18 z .................x
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[tex] \frac{24}{18} = \frac{1}{x} [/tex] marimile zile si lucrari sunt direct proportionale
[tex]x= \frac{18*1}{24}=0,75 [/tex]
10m ..............................18 z .............0,75 lucrare
10m-6m =4m .................y z ..............1-0,75=0,25 lucrare
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pastram numarul de muncitori
10m ..............................18 z .............0,75 lucrare
10m ...........................a zile ............0,25 l
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a=6 z
10m ...........................6 z ..............0,25
4 m y zile .........0,25
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[tex] \frac{10}{4} = \frac{y}{6}
[/tex] (nr. muncitori si nr. zile sunt invers proportionale
y=15 zile ( raspunsul)
