s1 suma primului
s2 suma celui de al 2-lea
s1/8 = s2/6=(s1+s2)/14 ⇒ (s1+s2)=14s1/8 (1)
s2/6+25s1/100+1100=s1+s2 ⇒ s2/6 + s1/4 +1100=s1+s2 (2)
din relatia (1) avem:s2/6=s1/8 si (s1+s2)=14s1/8 care le inlocuim in (2)
s1/8 + s1/4 +1100=14s1/8 de unde rezulta:
s1=800
s2=6s1/8=600