CxHyOz + H2 ⇒
M = 12x + y + 16z 12x = 0,4M x = M/30
y + 16z = 0,6M y = 16z/8 = 2z
2z + 16z = 0,6 M 18z = 0,6M z = M/30 = x y = M/15
CxH2xOx
nH2 = 8,96/22,4 = 0, 4 moli = n substanta
36/ M = 0,4 M = 90g/mol 12x + 2x + 16x = 90 30x = 90 x = 3
C3H6O3 reactioneaza cu r.Tollens ⇔ aldehida
HOOC-CH2-CH=O